x^2+12x-2880=0

Solution for x^2+12x-2880=0 equation:

x^2+12x-2880=0

a = 1; b = 12; c = -2880;
Δ = b2-4ac
Δ = 122-4·1·(-2880)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-108}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+108}{2*1}=\frac{96}{2}
=48
$